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문제 유형 빈칸 난이도 easy Note Nothing Code # -*- coding: utf-8 -*- # UTF-8 encoding when using korean def func_a(numA, numB, exp): if exp == '+': return numA + numB elif exp == '-': return numA - numB elif exp == '*': return numA * numB def func_b(exp): for index, value in enumerate(exp): if value == '+' or value == '-' or value == '*': return index def func_c(exp, idx): numA = int(exp[:idx]) numB = in..