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문제 유형 빈칸 난이도 easy Note Nothing Code # -*- coding: utf-8 -*- # UTF-8 encoding when using korean # 2차 2번 def func_a(times): hour = int(times[:2]) minute = int(times[3:]) return hour*60 + minute def solution(subway_times, current_time): current_minute = func_a(current_time) INF = 1000000000 answer = INF for s in subway_times: subway_minute = func_a(s) if subway_minute>=current_minute: answer = subw..