Development Artist

문제 유형 빈칸 난이도 easy Note 1. 수열 문제. 1 2 4 7 13 24 . . . Code # -*- coding: utf-8 -*- # UTF-8 encoding when using korean def solution(n): answer = 0 steps = [0 for _ in range(n+1)] steps[1] = 1 steps[2] = 2 steps[3] = 4 for i in range(4, n+1): steps[i] = steps[i-1] + steps[i-2] + steps[i-3] print(steps) answer = steps[n] return answer n1 = 3 ret1 = solution(n1) print("solution 함수의 반환 값은", ret1, "입니다..